Exercise 1.7.3
\[\begin{eqnarray*} x&=&(-y)^2-1\\ x&=&y^2-1\\ \end{eqnarray*}\]
Since this is the same as the original equation, the graph is symmetric with respect to the \(x\)-axis.
\[\begin{eqnarray*} x&=&(-y)^2-1\\ x&=&y^2-1\\ \end{eqnarray*}\]
Since this is the same as the original equation, the graph is symmetric with respect to the \(x\)-axis.