Exercise 1.7.4
\[\begin{eqnarray*} (-y)&=&(-x)^3\\ -y&=&-x^3\\ y&=&x^3 \end{eqnarray*}\]
Since this is the same as the original equation, the graph is symmetric with respect to the origin.
\[\begin{eqnarray*} (-y)&=&(-x)^3\\ -y&=&-x^3\\ y&=&x^3 \end{eqnarray*}\]
Since this is the same as the original equation, the graph is symmetric with respect to the origin.