Since the \(x\)-intercept is \(a=3\) and the \(y\)-intercept is \(b=2\) the intercept equation \(\dfrac{x}{a}+\dfrac{y}{b}=1\) gives the result \(\dfrac{x}{3}+\dfrac{y}{2}=1\). If we solve for \(y\) we get the slope-intercept version \(y=-\frac{2}{3}x+2\).