Exercise 2.2.6
Since the zeros are \(- 1\) and \(5\), the \(x\)-intercepts are \(( - 1, 0 )\) and \(( 5, 0 )\).
The \(x\)-coordinate of the vertex is \(-\dfrac{b}{2a} = 2\), so the \(y\)-coordinate is \(f ( 2 ) = 9\).
Since the zeros are \(- 1\) and \(5\), the \(x\)-intercepts are \(( - 1, 0 )\) and \(( 5, 0 )\).
The \(x\)-coordinate of the vertex is \(-\dfrac{b}{2a} = 2\), so the \(y\)-coordinate is \(f ( 2 ) = 9\).