Exercise 2.5.1

Applying the quadratic formula, we get

\[ x=\dfrac{-0\pm\sqrt{0^2-4}}{2} =\dfrac{\pm2\,i}{2}=\pm i\]

Using abbreviated synthetic division with \(\pm i\) we get

\(1\)\(0\)\(1\)
\(i\)\(1\)\(i\)\(0\)
\(-i\)\(1\)\(-i\)\(0\)

Which also shows us that \(x^2+1=(x-i)(x+i)\).