Exercise 3.4.1 solution

  1. \(\log_3 ( 9 ) = 1 - x\), so \(2 = 1 - x\). Thus, \(x = -1\).
  2. The equivalent statement in exponential form is \(2^1 = x^2 - x\). Thus, \(x^2 - x - 2 = 0\). This can be solved by factoring: \(( x - 2 ) ( x + 1 ) = 0\), thus \(x = 2\) or \(x = -1\).