Exercise 4.2.3 solution
\(\sin60^\circ=\text{ opp/hyp }=\dfrac{\sqrt{3}}{2}\)
\(\csc60^\circ=\text{ hyp/opp }=\dfrac{2}{\sqrt{3}}=\dfrac{2\sqrt{3}}{3}\)
\(\cos60^\circ=\text{ adj/hyp }=\dfrac{1}{2}\)
\(\sec60^\circ=\text{ hyp/adj }=2\)
\(\tan60^\circ=\text{ opp/adj }=\sqrt{3}\)
\(\cot60^\circ=\text{ adj/opp }=\dfrac{1}{\sqrt{3}}=\dfrac{\sqrt{3}}{3}\)