Exercise 4.5.3 solution
Let \(a\) denote the height of the flagpole. Then \(\dfrac{a}{50}=\tan48^\circ\), so \(a=50\tan48^\circ\approx55.5\) ft.
Let \(a\) denote the height of the flagpole. Then \(\dfrac{a}{50}=\tan48^\circ\), so \(a=50\tan48^\circ\approx55.5\) ft.