\(\begin{eqnarray*} y^2+4y&=&12x-40 \\ y^2+4x+4&=&12x-36\\ (y+2)^2&=&12(x-3) \end{eqnarray*}\)
Vertex is \((3,-2)\), Focus is \((6,-2)\), Directrix is \(x=0\).